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  1. 27 de abr. de 2024 · Respuesta: si El dominio de la función px = 2x - 3 es 1,01 ahí te está diciendo que f vale un número y aquí también pero si f no está concluido con x entonces x está redondeado por dos capas lo están cubriendo eso significa que f vale 2x y x vale 3 entonces 2x + 3 es 1,01 pero ahí le falta el cuatro entonces sería menos 1 ...

  2. 7 de may. de 2024 · So, f'(x)=(3*2)x^(3-1)-(2*30)x^(2-1)+(1*96)x^(1-1) f'(x)=6x^2-60x+96 Then, we set this derivative to zero and solve for x. The solutions are the critical numbers. To find the solutions, rewrite the equation into standard form: 6x^2-60x+96=0 Divide each term in the equation by 6 : x^2-10x+16=0

  3. 13 de may. de 2024 · 1 Identify the given functions: f (x)=2x+3 and g (x)=x^ {2}-2 g(x) =x2 − 2. 2 To find f (g (x)), substitute g (x) into f (x). So, f (g (x)) = f (x^ {2}-2) f (g(x)) = f (x2 −2) 3 Replace x in f (x) with x^ {2}-2 x2 −2 to get f (g (x)) = 2 (x^ {2}-2) + 3 f (g(x)) = 2(x2− 2)+3.

  4. Hace 1 día · For f(x,y) = 2(2x^2 + y^3)^4 (a) Determine fxx(x,y) (b) Determine fxy(x,y) (c) Determine fyy(x,y)Watch the full video at:https://www.numerade.com/ask/questio...

  5. 7 de may. de 2024 · Transcript. Ex 12.1, 23 (Method 1) Find lim┬ (x→0) f (x) and lim┬ (x→1) f (x), where f (x) = { (2x+3.@3 (x+1),)┤ 8 (x ≤0@x>0) Finding limit at x = 0 lim┬ (x→0) f (x) = lim┬ (〖x→0〗^− ) f (x) =lim┬ (〖x→0〗^+ ) f (x) ∴ (𝒍𝒊𝒎)┬ (𝐱→𝟎) f (x) = 3 (𝒍𝒊𝒎)┬ (〖𝐱→𝟎〗^− ...

  6. 2 de may. de 2024 · Answer by Amelia · May 2, 2024. Answer: Plot the functions f (x)= (2x+3)/x+1 and g (x)=ln (x+3) on Desmos or your favorite graphing tool. Answer the following with intervals. Approximations must be accurate to two decimal places. (a) What is the domain of f (g (x)) (b) What is the domain of g (f (x)).

  7. Hace 6 días · Example 1: Analyze the Local Maxima and Local Minima of the function f(x) = 2x 3 – 3x 2 – 12x + 5 by using the first derivative test. Solution: Given function is f(x) = 2x 33x 2 – 12x + 5. First derivative of function is f'(x) = 6x 2 – 6x – 12, it will use to find out the critical points.

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