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  1. Body-centered: H+K+L = 2n (even) H+K+L = 2n+1 (odd) Face-centered: H,K,L all odd or all even: H,K,L mixed odd, even: FCC Diamond: H,K,L all odd H,K,L all even and H+K+L = 4n: H,K,L mixed odd, even H,K,L all even and H+K+L 4n: Hexagonal (HCP) L even H+2K 3n: L odd and H+2K = 3n

  2. In three dimensions, end-centered, body-centered, and face-centered arrangements also produce extinctions. We often describe extinctions using arithmetical rules. For body centering, the rule is that an hkl peak will only be present if h + k + l is an even number.

  3. 24 de nov. de 2022 · The 7 Crystal Systems. The Body-Centered Cubic (BCC) unit cell can be imagined as a cube with an atom on each corner, and an atom in the cube’s center. It is one of the most common structures for metals. BCC has 2 atoms per unit cell, lattice constant a = 4R/√3, Coordination number CN = 8, and Atomic Packing Factor APF = 68%.

  4. By plugging in one of the entries from the table above, we can figure out what the lattice constant is. Let's use θ = 25.95 θ = 25.95 degrees and the (200) plane: Looking at the periodic table, an FCC element with lattice parameter around 3.52Å 3.52 Å is nickel! 6.16: X-ray Diffraction and Selection Rules.

  5. hkl for Face Centered Cubic • Substitute in a few values of hkl and you will find the following: – When h,k,l are unmixed (i.e. all even or all odd), then F hkl = 4f. [NOTE: zero is considered even] – F hkl = 0 for mixed indices (i.e., a combination of odd and even). Ffe e e 1 ih k ih l ik l() ( ) ( ) hkl Selection rules for hkl reflections

  6. Table 1.1 summarizes the selection rules (or extinction conditions as they are also known) for cubic lattices. According to these selection rules, the h2 + J<2 + [2 values for the different cubic lattices follow the sequence Primitive I, 2, 3,4, 5, 6, 8, 9, 10, 11, 12, 13, 14, 16, ... Body-centered 2,4, 6, 8, 10, 12, 14, 16, ...

  7. The conditions for systematic absences from body- and base-centred lattices can be derived in the same ways: either by referring the lattice to a primitive unit cell or by applying the structure factor equation. For example, for a body-centred cubic crystal with identical atoms at (000) and 1 2 1 2 1 2