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  1. The 'LS674 is a 16-bit parallel-in, serial-out shift register. A three-state input/output (SER/Q15) port provides access for entering a serial data or reading the shift-register word in a recirculating loop. The device has four basic modes of operation: Hold (do nothing) Write (serially via input/output) Read (serially) Load (parallel via data ...

  2. The 74F675A contains a 16-bit serial in/serial out shift reg- Serial-to-parallel converter ister and a 16-bit parallel out storage register. Separate 16-Bit serial I/O shift register serial input and output pins are provided for expansion to 16-Bit parallel out storage register longer words.

  3. The answer is that they actually only offer the serial-in, parallel-out shift register, as long as it has no more than 8-bits. Note that serial-in, serial-out shift registers come in bigger than 8-bit lengths of 18 to 64-bits. It is not practical to offer a 64-bit serial-in, parallel-out shift register requiring that many output pins.

  4. 74F676. 16-Bit Serial/Parallel-In, Serial-Out Shift Register. General Description Features. The 74F676 contains 16 flip-flops with provision for syn- 16-bit parallel-to-serial conversion chronous parallel or serial entry and serial output.

  5. The 74F673A contains a 16-bit serial-in, serial-out shift Serial-to-parallel converter register and a 16-bit Parallel-Out storage register. A single 16-bit serial I/O shift register pin serves either as an input for serial entry or as a 16-bit parallel-out storage register. 3-STATE serial output.

  6. The parallel-in/ serial-out shift register stores data, shifts it on a clock by clock basis, and delays it by the number of stages times the clock period. In addition, parallel-in/ serial-out really means that we can load data in parallel into all stages before any shifting ever begins.

  7. The datasheet refers to the 74HC595 as an "8-bit serial-in, serial or parallel-out shift register with output latches; 3-state." ... This means you can transmit 16 bits in a row (2 bytes) and the first 8 will flow through the first register into the second register and be expressed there.