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Hace 1 día · Luego, se aplicó pruebas de normalidad, incluyendo Lilliefors para análisis univariado y Mardia para el multivariado, para verificar los supuestos de normalidad. Si las variables no cumplen estos supuestos, se realizaron transformaciones utilizando la función bestNormalize de R Studio para aplicar la mejor transformación recomendada.
Hace 2 días · In ANSM5: Functions and Data for the Book "Applied Nonparametric Statistical Methods", 5th Edition ANSM5. The ANSM5 package provides a number of functions and data to accompany the book “Applied Nonparametric Statistical Methods”, 5th edition (Smeeton, Spencer & Sprent, 2024, Taylor Francis), the revisions from the 4th edition including a move from describing the output from a miscellany ...
Hace 2 días · A latent variable score of TM practices and networks was checked using the Kolmogorov–Smirnov test with Lilliefors correction approaches. The results indicated that none of the latent variables had a normal distribution. Then, the copula approach can be used to check the endogeneity problem in the model.
Hace 2 días · Lilliefors, H. W. 1967. On the Kolmogorov–Smirnov test for normality with mean and variance unknown. Journal of the American Statistical Association 62 :399–402. doi: 10.1080/01621459.1967.10482916.
Hace 5 días · This study used ominous Shapiro-Wilk (Shapiro & Wilk, 1965) as additional checks for multivariate normality since power comparisons with various normality tests, including Kolmogorov-Smirnov, Lilliefors, and Anderson-Darling, showed its superiority for asymmetric distributions (Razali and Wah, 2011, Yap and Sim, 2011).
Hace 3 días · Statistics document from University of Memphis, 6 pages, Madison Henderson Homework 4 HLSC 4400 - Statistics for Health Sciences Instructions: 1. Copy your answer to each question AND the output from SPSS by which you reached your answer to a document. The answers should be correctly ordered. 2. Provide your an
Hace 3 días · a. Lilliefors Significance Correction First, I conducted a diagnostic check for normality. Based on the Sig, 0.068 and 0.116 are both greater than 0.05, meaning the distribution is normal. Since the distribution is normal, we check for the equality of variances (Levene’s test – provided below).
