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Draw a labelled diagram of a d.c. motor. magnetic field, a torque acts on the coil which rotates it continuously. When the coil rotates, the shaft attached to it also rotates and thus it is able to do mechanical work. The main parts of electric motor are the magnets, armature, split ring commutators and brushes.
Answer. (a) Draw a labelled diagram of a step-up transformer. Obtain the ratio of secondary to primary voltage in terms of number of turn and currents in the two coils. (b) A power transmission line feeds input power at 2200 V to a step-down transformer with its primary windings having 300 turns.
(a) Priciple and working: When current (I) is passed in the coil, torque τ acts on the coil, given by τ = NIABsin θ . where θ is the angle between the normal to plane of coil and the magnetic field of strength B, N is the number of turns in a coil.. When the magnetic field is radial, as in the case of cylindrical pole pieces and soft iron core, then in every position of coil the plane of ...
Principle and working: When current ( I) is passed in the coil, torque T acts on the coil, given by. T = N I A B sin. . θ. Where θ is the angle between the normal to plane of coil and the magnetic field or strength B, N is the number of turns in a coil. A current carrying coil, in the presence of a magnetic field, experience a torque, which.
Explain. Moving coil galvanometer is an instrument used for the detection and measurement of small currents. Principle: The working of moving coil galvanometer is that when a current carrying coil is placed in a varying magnetic field, it experiences torque. Consider a rectangular coil for which no. of turns = N. Are of cross-section is A = lb.
A circular coil of wire consisting of 100 turns, each of radius 8.0 cm carries a current of 0.40 A. What is the magnitude of the magnetic field B at the centre of the coil? Magnetic lines of force always cross each other. A circular coil carrying a current I has radius R and number of turns N. If all the three, i.e. the current
Therefore we write, Sensitivity = dθ/di. If a galvanometer gives a larger deflection for a small current it is a sensitive galvanometer. The current in Moving Coil galvanometer is: I = (C/nBA) × θ. Therefore, θ = (nBA/C) × I. Differentiating on both sides wrt I, we have: dθ/di = (nBA/C). To sum up, the sensitivity of Moving Coil ...
