Resultado de búsqueda
Jake Joseph Paul (Cleveland, Ohio; 17 de enero de 1997) [1] es una personalidad de Internet, actor y boxeador estadounidense. Inicialmente saltó a la fama en la ahora desaparecida aplicación de video Vine, [2] antes de interpretar el papel de Dirk Mann en la serie Bizaardvark de Disney Channel durante dos temporadas. [3]
6 de ago. de 2023 · Jake Paul comes away with a victory over MMA legend Nate Diaz in a 10-round cruiserweight bout via unanimous decision.
Jake Joseph Paul (born January 17, 1997) is an American YouTuber, actor, and professional boxer. He began his career posting videos on Vine in September 2013 and had amassed 5.3 million followers and 2 billion views before the app discontinued.
I'm Jake Paul. 27 y/o pro boxer / musical artist FAHLO ME OTHER SOCIAL MEDIAS Instagram: jakepaul Twitter: jakepaul Snapchat: jakepaul19 Business: brands@jakepaul.com
7 de mar. de 2024 · (CNN) -- El youtuber convertido en boxeador Jake Paul se enfrentará a la leyenda del peso pesado Mike Tyson en un combate de exhibición de boxeo el 20 de julio. El evento se transmitirá...
Jake Paul 9: 1: 0: 6 KOs 0 KOs; 951 followers Box-pro promoter division: cruiser rating #121 / 1,266 #16 / 183 ... Paul and Fury deducted one point for fouls. Fury down in round eight. 2022-10-29: Anderson Silva: 3 1 0: Gila River Arena, Glendale W-UD.
5 de ago. de 2023 · Jake Paul beat Nate Diaz by unanimous decision Saturday night at the American Airlines Center in Dallas. Diaz, the MMA star who was making his pro boxing debut, was the clear favorite of the...
We would like to show you a description here but the site won’t allow us.
Hace 6 días · Jake Paul: Everyone's in the wrong after news conference skirmish; Woodley, Paul's crew get into heated exchange; Jake Paul loss just a distant memory for groundhog hater and buckthorn slayer...
30 de oct. de 2022 · Jake Paul venció a la leyenda de la UFC Anderson Silva por puntos y continúa invicto en su carrera como púgil en seis peleas que lleva disputadas. La estrella estadounidense de Yo.
