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14 de may. de 2024 · Explanation: f(x)=2eta^3-21eta^2+72eta -2 f'(n)=frac dd_n[2n^3-21n^2+72n-2] =2 dx^3/dx -21 dx^2/dx +72 dx/dx - dz/dx =2(3y^2)-21(2x)+72-0 f'(x)=6x^2-42x+72 for Contical numbero do f'(n)=0 6x^2-42x+72=0 6(x^2-7x+12)=0 ) 7^2-7x+12=0 x^2-4x-3x+12=0 x(x-4)-3(x-4)=0 (x-3)(x-4)=0 =) x=3.4 A f'(x)=6x^2-42x+72=6(x-3)(x-4) Sign Sme for f'(n ...
6 de may. de 2024 · Answer by Bruce · May 6, 2024. Answer: Increasing : (-∈fty ,-4), (-2,∈fty ) Decreasing : (-4,-2). Explanation: f (x)=2x^3+18x^2+48x f' (x)=6x^2+36x+48 f' (x)=0 6 (x^2+6x+8)=0 (x+4) (x+2)=0 x+4=0 V x+2=0 x=-4 x=-2 -4 -2 Inc. Dec. Inc. ln c.= (-∈fty ,-4)∪ (-2,∈fty ) Dec.= (-4,-2) Table 1: [] Copy. Need improvement.
11 de may. de 2024 · Explanation: Explanation Firstly, let's compute the derivative of f , f'(x) , because its roots will give us the critical points: f'(x)=6x^2+18x-24. Setting f'(x) equal to zero gives us the critical points: 6x^2+18x-24=0 This simplifies down to: x^2+3x-4=0 Factoring this quadratic equation gives us the roots: (x+4)(x-1)=0 Setting ...
20 de may. de 2024 · Solve for x: x = 6 - 2. x = 4. Solution: x = 4, y = 1.5. Test the solution: 3 × 4 - 4 × 1.5 = 12 - 6 = 6. We see that the first equation is OK.-4 + 4 × 1.5 = -4 + 6 = 2. And the second equation is OK as well. Solve using substitution method: 2x + 3y = 5. 2x + 7y = -3. Solve the first equation for x: x = -1.5y + 2.5. Substitute x ...
Hace 4 días · First, we can simplify the equation by factoring out common factors in the numerator and the denominator. In the numerator, we can factor out 3: f. f ( x) = 3 ( x + 4) x ( 2 ( x + 2)) Now, we can see that (x+4) is a common factor in the numerator and the denominator, so we can cancel it out: f ( x) = 3 2 x So, the simplified form of the ...
Hace 5 días · 24 (2)^ (x - 1) + 16. The graph of g (x) is a transformation of the graph of f (x)=3^x. Enter the equation for g (x) in the box. g (x) =. 3^ (x - 2) - 1. The graph shows the parent function f (x)=0.75x. https://static.k12.com/nextgen_media/assets/8079938-NG_AL1_SemA_06_UT_19.png.
21 de may. de 2024 · We will now see how to perform a synthetic division if the divisor is in the form b 1 x + b 0, i.e., linear but not necessarily monic.As an example, let's divide 4x 3 + 2x 2 - 2x + 1 by 2x + 1.. Set up the division table. It's very similar to that for monic divisors, but the main difference is the presence of the fourth row, where we place the leading coefficient b 1 of the divisor preceded by ...
