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  1. Algebra Examples. Popular Problems. Algebra. Graph f (x)=2x^2+4x-5. f (x) = 2x2 + 4x − 5 f ( x) = 2 x 2 + 4 x - 5. Find the properties of the given parabola. Tap for more steps... Direction: Opens Up. Vertex: (−1,−7) ( - 1, - 7) Focus: (−1,−55 8) ( - 1, - 55 8) Axis of Symmetry: x = −1 x = - 1. Directrix: y = −57 8 y = - 57 8.

  2. Linear equation. Arithmetic. Matrix. Simultaneous equation. Differentiation. Integration. Limits. Solve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more.

  3. Álgebra Ejemplos. Problemas populares. Álgebra. Gráfico f (x)=x^2-4x-5. f (x) = x24x5 f ( x) = x 2 - 4 x - 5. Obtén las propiedades de la parábola dada. Toca para ver más pasos... Dirección: abre hacia arriba. Vértice: (2,−9) ( 2, - 9) Foco: (2,− 35 4) ( 2, - 35 4) Eje de simetría: x = 2 x = 2. Directriz: y = −37 4 y = - 37 4.

  4. Popular Problems. Precalculus. Find the Vertex f (x)=-2x^2+4x-5. f (x) = −2x2 + 4x − 5 f ( x) = - 2 x 2 + 4 x - 5. Rewrite the equation in vertex form. Tap for more steps... y = −2(x−1)2 −3 y = - 2 ( x - 1) 2 - 3. Use the vertex form, y = a(x−h)2 +k y = a ( x - h) 2 + k, to determine the values of a a, h h, and k k. a = −2 a = - 2. h = 1 h = 1.

  5. Quadratic formula. En álgebra elemental, la fórmula cuadrática es una expresión de forma cerrada que describe las soluciones de una ecuación cuadrática. Otras formas de resolver ecuaciones cuadráticas, como completar el cuadrado, producen las mismas soluciones.

  6. y=\frac{x}{x^2-6x+8} f(x)=\sqrt{x+3} f(x)=\cos(2x+5) f(x)=\sin(3x) Mostrar mas; Descripción. Explora funciones paso por paso functions-calculator. es. Entradas de blog de Symbolab relacionadas. Functions. A function basically relates an input to an output, there’s an input, a relationship and an output.

  7. 2 de ago. de 2016 · 1 Answer. Rachel. Aug 2, 2016. 2(x +1)2 −7. Explanation: We begin with y = 2x2 + 4x −5. We need to rewrite this into vertex form. The easiest way to do that is to complete the square. This is a very useful way to factor, and I don't want to spend too much time explaining it right now, but I'll cover it as I go.