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6 de abr. de 2020 · 999999999.99999999 is a double constant, but there is no double that can model that exact value, so the one closest to it is picked, and that is 100000000. It doesn't matter that it's passed as an argument to a constructor of an object capable of representing your original number: by then the reversion to the nearest double has already taken place.
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6 de dic. de 2016 · The max value of and int variable is 999999999 * 10 which is max 10 digits. If your loop is set to run the value of NUM times until it reaches 9. If we let's say pick the lowest possible 16 digit credit card number, 1000000000000000, your loop still will still run 1000000000000000 - 9 times.
111. Erlang was reported to have been used in production systems for over 20 years with an uptime percentage of 99.9999999%. I did the math as the following: 20*365.25*24*60*60*(1 - 0.999999999) == 0.631 s. That means the system only has less than one second of downtime during the period of 20 years. I am not trying to challenge the validity of ...
15 de jul. de 2010 · Viewed 20k times. 3. I want to generate random number, which is 9 digits including leading zero if the number is less than 9 digits, say 123 will be 000000123. I have the following code which doesn't include leading zero : Dim RandomClass As New Random () Dim RandomNumber = RandomClass.Next (1, 999999999) Thanks. vb.net.
8 de mar. de 2015 · Add the line num = (num % (999999999 - 100000000)) + 100000000; to generate a random number of the lower limit of 100000000 and the upper limit of 999999999. – David M. Syzdek. Oct 27, 2011 at 21:24. 2. Better, but now the numbers above 805933941 (2^64 -1 mod 899999999) are slightly less probable than the numbers below ;-) – undur_gongor.
1 de jun. de 2016 · 9999999999is outside the valid range of values for the intdata type (-231to 231-1, inclusive), as specified by the Integer.MIN_VALUEand Integer.MAX_VALUEconstants. You cannot represent a full phone number in an int, you would have to omit the prefix and area code (0000000 - 9999999). Otherwise, use a longinstead (-263to 263-1, inclusive), Long ...
1 de dic. de 2019 · Puedes usar la clausula HAVING como te indican en la otra respuesta, pero yo lo haría sobre la propia formula de la ganancia, es decir: HAVING sum(d.venta_sali - d.costo_sali) > 40000. De esta forma la condición es sobre datos numéricos (más eficiente), no sobre un campo VARCHAR formateado, en el ejemplo, el valor de Ganancia es un VARCHAR ...
5 de ene. de 2009 · 999999999*999999999=999999998000000001 看出有什么规律了吧。 如果有几个9乘以相同的几个9就等于几减一个9后面一个8再有几减一个0后面一个一。
19 de sept. de 2008 · 2^32 = 4294967296wait ... you only have 32 bits, that is index 0-31. To get max value you actually have to calculate the sum of 2^nwith n from 0 to 31 or simpler 2^32 - 1and you'll get '4294967295' as max for unsigned int, one less than anticipated. Now do the same with 2^31 - 1for signed int and you'll get 2,147,483,647.
